If 1022 gas molecules each of mass 10–26 kg collide with a surface (perpendicular to it) elastically per second over an area 1 m2 with a speed 104 m/s the pressure exerted by the gas molecules will be of the order of –

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asked Sep 12 in Science by navnit40 (-4,766 points)

If 1022 gas molecules each of mass 10–26 kg collide with a surface (perpendicular to it) elastically per second over an area 1 m2 with a speed 104 m/s the pressure exerted by the gas molecules will be of the order of –

(1) 108 N/m2  (2) 104 N/m (3) 1016 N/m2 (4)  2 N/m

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answered Sep 12 by muskan15 (-3,447 points)

Correct option  (4)  2 N/m2

Explanation:

P = (2Mv)N/A =  (2(10-26)(104)1022)/1 = 2.N/m2

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