In an interference experiment the ratio of amplitudes of coherent waves is a_{1}/ a_{2} = 1/3 . The ratio of maximum and minimum intensities of fringes will be –
(1) 9
(2) 2
(3) 18
(4) 4
Correct option (4) 4
Explanation:
a_{1 }: a_{2} = 1 : 3
I_{1}/I_{2} = (4/2)^{2} = 4 : 1