Three resistances are connected in series across 12 volt battery.

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asked Sep 12 in Science by priya12 (-12,583 points)

Three resistances are connected in series across 12 volt battery. The first resistor has value of 1 ohm second has voltage drop of 4 volt and third has power dissipation of 12 watt. What is circuit current.

(a) 1A

(b) 2A

 (c) 3A

(d) 4A

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1 Answer

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answered Sep 12 by navnit40 (-4,766 points)

Correct option(b)

 Explanation:

V = v1 + v2 + v3

12 = I × 1 + 4 + 12/1

I + 12/I = 8

I2 + 12 = 81

I2 – 81 + 12 = 0

I = 2A

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