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in Class VII Maths by (-2,181 points)

A box contains 3 yellow, 4 green and 8 blue tickets. A ticket is chosen at random. Find the probability that the ticket is :
(i) yellow
(ii) green
(iii) blue
(iv) red
(v) not yellow

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1 Answer

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Number of yellow tickets = 3

Number of green tickets = 4

Number of blue tickets = 8

Total Number of tickets = 3 + 4 + 8 = 15

(i) P (getting a yellow ticket) = 3/15 = 1/5

(ii) P (getting a green ticket) = 4/15

(iii) P (getting a blue ticket) = 8/15

(iv) Since, Basket contains yellow, green and blue tickets only.

∴ Number of red tickets = 0

∴ P (getting an red ticket) = 0/15 = 0

(v) Total number of green and blue tickets = 4 + 8 = 12 tickets

P (not getting yellow ticket) = P(getting either green or blue ticket) = 12/15 = 4/5

OR,

P (not getting a yellow ticket) = 1 – (1/5) = (5 – 1)/5 = 4/5

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