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In a cricket match a batsman hits a boundary 12 times out of 80 balls he plays further if he plays one ball more what will be the probability that:
(i) he hits a boundary
(ii) he does not hit a boundary

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(i) Total number of balls = 80

Hits boundaries = 12 times

∴ P (Hitting a boundary) = 12/80 = 3/20

(ii) P (of not hitting a boundary) = 68/80 = 17/20

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