Total outcomes = 36 i.e.
(1,1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5 , 6)
(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
(i) Favourable Outcomes = 0
P(E) = 0/36 = 0
(ii) Favourable outcomes = 1 I.e. (6, 6)
P(E) = 1/36
(iii) Favourable outcomes = 35 [Except (6, 6)]
P(E) = 35/36
(iv) Favourable outcomes = 36
P(E) = 36/36 = 1