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Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is:
(i) 0
(ii) 12
(iii) less than 12
(iv) less than or equal to 12

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Total outcomes = 36 i.e.

(1,1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5 , 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(i) Favourable Outcomes = 0

P(E) = 0/36 = 0

(ii) Favourable outcomes = 1 I.e. (6, 6)

P(E) = 1/36

(iii) Favourable outcomes = 35 [Except (6, 6)]

P(E) = 35/36

(iv)  Favourable outcomes = 36

P(E) = 36/36 = 1

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