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In a single throw of a die, find the probability of getting :
(i) 8
(ii) a number greater than 8
(iii) a number less than 8

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1 Answer

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On a die the numbers are 1, 2, 3, 4, 5, 6 i.e. six.
∴ Number of possible outcome = 6

(i) Number of favourable outcome = 0

(∵ 8 is not possible)

∴ P(E) = Number of favourable outcome/Number of all possible outcome

= 0/6 = 0

(ii) Number greater than 8 will be 0

∴ P(E) = Number of favourable outcome/Number of all possible outcome

= 0/6 = 0

(iii) Number less than 8 will be 1, 2, 3, 4, 5, 6

∴ P(E) = Number of favourable outcome/Number of all possible outcome

= 6/6 = 1

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