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In a single throw of a die, find the probability that the number:
(i) will be an even number.
(ii) will be an odd number.
(iii) will not be an even number.

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A die has six numbers: 1, 2, 3, 4, 5, 6
∴ Number of possible outcome = 6
(i) Number of favourable outcome = an even number i.e. 2, 4, 6 which are 3 in numbers

∴ P(E) = Number of favourable outcome/Number of all possible outcome

= 3/6 = 1/2

(ii) & (iii) Number of favourable outcome = not an even number i.e. odd numbers :

1, 3, 5 which are 3 in numbers

∴ P(E) = Number of favourable outcome/Number of all possible outcome

= 3/6 = 1/2

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