A die has six numbers: 1, 2, 3, 4, 5, 6
∴ Number of possible outcomes = 6
(i) a prime number
Number of favourable outcomes = a prime number = 1, 3, 5 which are 3 in numbers
P(E) = Number of favourable outcomes/Number of all possible outcomes
= 3/6 = 1/2
(ii) Number of favourable outcomes = greater than four i.e. two number 5 and 6
∴ P(E) = Numbers of favourable outcomes/Number of all possible outcomes
= 2/6 = 1/3
(iii) Number of favourable outcome = not greater than 4 or numbers will be 1, 2, 3, 4 which are 4 in numbers
∴ P(E) = Numbers of favourable outcome/Number of all possible outcome
= 4/6 = 2/3