Solve: (2x + 1)/3 + 15 < 17; x ∈ W

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asked May 25 in Class VIII Maths by navnit40 (-4,678 points)

Solve: (2x + 1)/3 + 15 < 17; x ∈ W

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answered May 25 by priya12 (-12,524 points)

(2x + 1)/3 + 15 < 17; x ∈ W

⇒ (2x + 1)/3 ≤ 17 – 15 = 2

⇒ 2x + 1 ≤ 6 ⇒ 2x ≤ 5

⇒ x ≤ (5/2) = 2. ½

But x ∈ W

∴ x = 0, 1, 2

∴ Solution set is = {0, 1, 2}

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