An exhibition tent is in the form of a cylinder surmounted by a cone.

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asked Mar 19 in Class X Maths by priya12 (-11,659 points)

An exhibition tent is in the form of a cylinder surmounted by a cone. The height of the tent above the ground is 85 m and the height of the cylindrical part is 50 m. If  the diameter of the base is 168 m, find the quantity of canvas required to make the tent. Allow 20% extra for folds’ and for stitching. Give your answer to the nearest m2.

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answered Mar 19 by muskan15 (-2,477 points)

Radius of box = 168/2 = 84 m

Height of the cone = 35 m

Height of cylinder = 50 m

Curved surface area of the tent = 2πrh + πrl

= 2 × 22/7 × 84 × 50 + 22/7 × 84 × 91   [l2 = (35)2 + (84)2] i.e., l = 91]

44 ×12 × 50 + 22 × 12 × 91

= 26400 + 24024

= 50424 sq. m

Area of the canvas required with (20% extra)

= 120/100 × 50424 = 60508.8 sq. m

= 60509 m2

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