The radius of two right circular cylinder are in the ratio of 2 : 3 and their heights are in the ratio 5 : 4 calculate the ratio of their curved surface areas and also the ratio of their volumes.

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asked Mar 18 in Class X Maths by aditya23 (-1,396 points)

The radius of two right circular cylinder are in the ratio of 2 : 3 and their heights are in the ratio 5 : 4 calculate the ratio of their curved surface areas and also the ratio of their volumes.

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answered Mar 18 by priya12 (-11,659 points)

Let the radii of two cylinders be 2r and 3r respectively and their heights be 5h and 4h respectively. Let S1 and S2 be curved Surface area of the two cylinders and V1 and V2 be their volumes.

Then, S1 = Curved surface area of the cylinders of height 5h and radius 2r

⇒  2π × 2r × 5h = 20πrh sq., units

S2 = Curved surface area of cylinder of height 4h and radius 3r

= 2π × 3r × 4h = 24πrh

S1/S2 = 20πrh/24πrh = 5/6 ⇒ S1: S2 = 5 : 6

V1 = Volume of cylinder of height 5h and radius 2r = π × (2r)2 × 5h = 20πr2h cubic units

V2 = Volume of cylinder  of height 4h and radius 3r = π × (3r)2 × 4h = 36 πr2h cubic units

∴  V1/V2 = 20πr2h/36 πr2h = 5/9 ⇒ V1 : V2 = 5 : 9

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