In the given figure below, ABCD is a rectangle. AB = 14 cm, BC = 7 cm.

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asked Mar 18 in Class X Maths by muskan15 (-1,962 points)

In the given figure below, ABCD is a rectangle. AB = 14 cm, BC = 7 cm. From the rectangle, a quarter circle BFEC and a semicircle DGE are removed. Calculate the area of the remaining piece of the rectangle. (Take π = 22/7)

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answered Mar 18 by priya12 (-11,081 points)

Length of rectangle(l) = 14 cm

Breadth = 7 cm

Radius of quarter circle r1 = 7 cm

Radius of semi-circle r2 = 7/2 cm

Area of remaining portion = Area of rectangle – (area of quadrant + area of semicircle)

= l × b – (πr12/4 + πr22/2)

= 14 × 7 – (22/7 × 1/4 × 7 × 7 + 22/7 × ½ × 7/ 2 × 7/2)

= 98 – 77/2 – 77/4

= (392 – 154 – 77)/4 = 161/4

= 40 ¼ sq. units

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