X
Free Study Rankers App Download Now
0 votes
813 views
in Class XII Maths by (-2,838 points)

Find a point on the curvey y = (x - 3)2, where the tangent is parallel to the chord joining the points (3,0) and (4,1). 

 

Please log in or register to answer this question.

1 Answer

0 votes
by (-1,017 points)

We have, y = (x-3)2, which is polynomial function .
So it is continuous and differentiable .
Thus condition of mean value theorem are satisfied.
Hence, there exists atleast one c ∈ (3,4) such that , 

Related questions

0 votes
1 answer
StudyrankersApp

Categories

...